I understand what it means to reach the memory that it is a coalition, but I do not understand why this Necessary. For example, how can I use a byte from an address 0x ... 1
but I can not use one half word (two bytes) from the same address.
Again, I understand that if you have an address of A
and s , then the entry is aligned if A mod S = 0
. But I do not understand why it is important at the hardware level.
The hardware is complex; This is a simple explanation.
A typical modern computer may have a 32-bit data bus, which means that any fitch that needs to be done will receive a special memory address for all 32 bits . Since the data can not just fetch anything less than 32 bits, so at least two address bits are not used on the address bus, so it seems that the 32-bit words < / Em> instead of 8-bit bytes .
When the CPU does one fetch for a byte, then the reading cycle will bring 32 bits and then the CPU will end 24. Those bits, the remaining 8 bits which are loaded in the register If the CPU wants to get 32 bit value which is a not alliance on the 32-bit limit, then there are several common options in it:
Two separate reading Execute chakras with just loading the appropriate parts of the word word and Read something Throw out an exception Read the 32-bit word at the address specified by throwing at least two bits of the address < / Li> I have worked with several CPUs, which have taken four out of four, usually those paths, for maximum compatibility it all aligns the N-bit to read in the N-bit range Is the safest. However, you can definitely take shortcuts if you are sure that your software will run with a specially identifiable behavior known to the CPU family. And if untrained reading is also possible (such as x86 family on CPU), then they will be slow
Popular posts from this blog
I am getting an error with php in order to format mysql_query () in php to format this string What is the right way? SELECT SELECT SELECT (*) Agents @AgentCount; User_Agent_English, User_Angent_Oursal, US.___Gent_Aginal, COUNT (User_Agent_Percade) ACC, COUNT (*) / (AgentCount) Percentage by agents user_agent_preser order DEC limit limit 50; In PHP, how am i setting $ query $ query = "SELECT count (*) agents @ agentcount; SELECT user_agent_parsed, User_agent_original , COUNT (user_agent_parsed) ascount, COUNT (*) / (@AgentCount) as a percentage by user_agent_parced by URI date DESC limit 50 "; This exact query will work properly if I put it in MySQL directly through a command line session. Do I need to release two separate php calls from mysql_query () and store the results first? I get the following error: There is an error in your SQL syntax; Instead of using a sub-selection and instead of using the 'SELECT user_agent_parsed, user_agent_original, ne...
Does Laravel's routing work as expected? What I think, if I want to override a route, then I just have to give the expected route before each other. I have something like this: root :: group (array ('first' = & gt; 'defaultLoads' =); function () {root :: post 'Newsletter', 'newsletter controller @ store'); root: group (array ('(newsletter', 'newsletter controller');}}); That if I post this route, only http://domain.com/newsletter should run only the default loads route filter. However, when I call php Runs artisan routes , I get this: | | POST newsletter | newsletter.store | newslettercontroller@ store | default loads | login | | though it reads the route correctly (PHP artisan loads which The correct path is to the right place) but the file of the resource path even if it is not in the filter group, the path is affected. Then my question: How does it work Laravel? If so, do I post this -> Newsle...
This URL should work even after the rewrite. Is this possible? Otherwise, I can only hardcoded everything If you are trying to create a login system with redirection You need to use the HTTP_REFERER header to find out where the user came from so that you can send it back there. The best way to do this is to use something like this in your login form: // - Login php & Lt; Input type = "password" name = "password" /> & Lt; Input type = "hidden" name = "returnrelale" value = "& lt ;? php echo $ redirectURL ;? & gt;" / & Gt; & Lt; / Form & gt; Please note that some ISP, browser or proxy will delete the referrer header, so you can not rely on each user to work fully. If you use a statement, to check whether the header exists or not, you can send those users back to the homepage or whatever. Edit If you are looking to use $ _SERVER ['REQUEST_URI'], if you are running Apache It sho...