inheritance - How can I call a masked function in C++? -

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Assume that I have this C ++ code: 

  zero example function ( ) {// # 1 cot and lt; & Lt; "I want to call the function." & Lt; & Lt; Endl; } Class ExampleParent {// I have no control over the public of this class: zero example function () {// # 2 cout & lt; & Lt; "I do not want to call the function." & Lt; & Lt; Endl; } // other stuff}; Class examples: Groups: Public for example {Public: My job is zero () (example) function (); // How to get # 1? }};

I have a succession from parent class to customize some of the functionality in the frame. However, parent class global < Code> exampleFunction is the one I want to call. Is there a way I can call it with myFunction ?

(The time function

Do the following: 

 : exampleFunction ()

::

If you include # & lt; ctime & gt; , you name it as a std :

To avoid these problems, keep everything in the name space, And by using the global namespace.


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