c# - Unable to detect right mouseclick in ComboBox -

-

मेरे पास एक कॉम्बो बॉक्स है जो एक साधारण ड्रॉप डाउन शैली है

मेरा कोड: 

 मैं एक नई विंडो खोलना चाहता था जब उपयोगकर्ता सही सूची में एक आइटम पर क्लिक करता है, लेकिन मुझे एक सही क्लिक का पता लगाने में परेशानी हो रही है। 
  निजी शून्य cmbCardList_MouseClick (ऑब्जेक्ट प्रेषक, MouseEventArgs ई) {if (e.button == MouseButtons.Right और amp; cmbCardList.SelectedIndex! = -1) {frmViewCard vc = new frmViewCard (); vc.updateCardDisplay (cmbCardList.SelectedItem); vc.Show (); }}

अगर मैं ई.बटन == माउसबुटन्स बदलता हूं। पूरी बात को ठीक से बंद करें। किसी भी तरह से मैं यह काम कर सकता हूँ जैसे मेरा इरादा है?

मुझे डर है कि जब तक यह मान्य नहीं होगा आप कुछ गंभीर हैकिंग करते हैं यह आपको समझाएगा।

आपके लिए उद्धरित:

व्यक्तिगत नियंत्रण

निम्न नियंत्रण मानक माउस क्लिक इवेंट के अनुरूप नहीं होते हैं व्यवहार:

बटन, चेकबॉक्स, कॉम्बोबॉक्स , और रेडियो बटन नियंत्रण

  • वाम क्लिक करें: क्लिक करें, माउसक्लिक

  • राइट क्लिक करें: क्लिक नहीं किए गए इवेंट्स

  • बायां डबल क्लिक करें: क्लिक करें, माउसक्लिक; क्लिक करें, माउसक्लिक

  • राइट डबल-क्लिक करें: क्लिक नहीं किए गए इवेंट्स


Comments

Post a Comment

Popular posts from this blog

MySql variables and php -

-
I am getting an error with php in order to format mysql_query () in php to format this string What is the right way? SELECT SELECT SELECT (*) Agents @AgentCount; User_Agent_English, User_Angent_Oursal, US.___Gent_Aginal, COUNT (User_Agent_Percade) ACC, COUNT (*) / (AgentCount) Percentage by agents user_agent_preser order DEC limit limit 50; In PHP, how am i setting $ query $ query = "SELECT count (*) agents @ agentcount; SELECT user_agent_parsed, User_agent_original , COUNT (user_agent_parsed) ascount, COUNT (*) / (@AgentCount) as a percentage by user_agent_parced by URI date DESC limit 50 "; This exact query will work properly if I put it in MySQL directly through a command line session. Do I need to release two separate php calls from mysql_query () and store the results first? I get the following error: There is an error in your SQL syntax; Instead of using a sub-selection and instead of using the 'SELECT user_agent_parsed, user_agent_original, ne...
Read more

php - Laravel - Overriding a resource route into a different route filter group -

-
Does Laravel's routing work as expected? What I think, if I want to override a route, then I just have to give the expected route before each other. I have something like this: root :: group (array ('first' = & gt; 'defaultLoads' =); function () {root :: post 'Newsletter', 'newsletter controller @ store'); root: group (array ('(newsletter', 'newsletter controller');}}); That if I post this route, only http://domain.com/newsletter should run only the default loads route filter. However, when I call php Runs artisan routes , I get this: | | POST newsletter | newsletter.store | newslettercontroller@ store | default loads | login | | though it reads the route correctly (PHP artisan loads which The correct path is to the right place) but the file of the resource path even if it is not in the filter group, the path is affected. Then my question: How does it work Laravel? If so, do I post this -> Newsle...
Read more

url rewriting - How to implement the returnurl like SO in PHP? -

-
This URL should work even after the rewrite. Is this possible? Otherwise, I can only hardcoded everything If you are trying to create a login system with redirection You need to use the HTTP_REFERER header to find out where the user came from so that you can send it back there. The best way to do this is to use something like this in your login form: // - Login php & Lt; Input type = "password" name = "password" /> & Lt; Input type = "hidden" name = "returnrelale" value = "& lt ;? php echo $ redirectURL ;? & gt;" / & Gt; & Lt; / Form & gt; Please note that some ISP, browser or proxy will delete the referrer header, so you can not rely on each user to work fully. If you use a statement, to check whether the header exists or not, you can send those users back to the homepage or whatever. Edit If you are looking to use $ _SERVER ['REQUEST_URI'], if you are running Apache It sho...
Read more