Include Elements in XSD Complex Type Without New Element -

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मेरे पास यह जटिल प्रकार है: 

  & lt; xsd: जटिल टाइप नाम = "आइडेंटिफ़ायर" & gt; & LT; XSD: अनुक्रम & gt; & Lt; xsd: तत्व का नाम = "आईडी" प्रकार = "xsd: स्ट्रिंग" / & gt; & Lt; xsd: तत्व का नाम = "संस्करण" प्रकार = "xsd: स्ट्रिंग" / & gt; & Lt; / XSD: अनुक्रम & gt; & Lt; / XSD: complexType & gt;

अब मैं इसे एक और जटिल प्रकार में शामिल करना चाहता हूं और मैं ऐसा कर रहा हूं: 

  & lt; xsd: जटिल टाइप & gt; & LT; XSD: अनुक्रम & gt; & Lt; xsd: तत्व का नाम = "आईडी" प्रकार = "पहचानकर्ता" / & gt; & Lt;! - यहां अतिरिक्त तत्व - & gt; & Lt; / XSD: अनुक्रम & gt; & Lt; / XSD: complexType & gt;

यह नहीं है कि मैं वास्तव में हालांकि चाहता हूं। मैं एक नए तत्व के बिना पहचानकर्ता प्रकार के तत्वों को सीधे अपने दूसरे जटिल प्रकार में शामिल करना चाहता हूं। जैसे ऐसा करने के समान ही: 

  & lt; xsd: जटिल टाइप & gt; & LT; XSD: अनुक्रम & gt; & Lt; xsd: तत्व का नाम = "आईडी" प्रकार = "xsd: स्ट्रिंग" / & gt; & Lt; xsd: तत्व का नाम = "संस्करण" प्रकार = "xsd: स्ट्रिंग" / & gt; & Lt;! - यहां अतिरिक्त तत्व - & gt; & Lt; / XSD: अनुक्रम & gt; & Lt; / XSD: complexType & gt;   
 
 "पोस्ट-पाठ" itemprop = "   
 पाठ "> 
 आप इस तरह से प्रकार बढ़ा सकते हैं:  
  & lt; xsd: जटिल टाइप नाम =" माइस्बटीप "& gt; & LT; XSD: complexContent & gt; & Lt; xsd: एक्सटेंशन बेस = "आइडेंटिफ़ायर" & gt; & LT; XSD: अनुक्रम & gt; & Lt;! - यहां अतिरिक्त तत्व - & gt; & Lt; / XSD: अनुक्रम & gt; & Lt; / XSD: विस्तार & gt; & Lt; / XSD: complexContent & gt; & Lt; / XSD: complexType & gt;

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