xml - SQL Server 2005 Xquery namespaces -

-

I am trying to exclude certain values ​​from the XML datatype. Data looks like this: 

  & lt; Personalized xmlns: xsi = "http://www.w3.org/2001/XMLSchema-instance" xmlns: xsd = "http: // www. W3.org/2001/XMLSchema"> & Lt; Firstname xmlns = "http://nswcc.org.au/BusinessEntities.Crm" & gt; Liria & lt; / FirstName & gt; & Lt; LastName xmlns = "http://nswcc.org.au/BusinessEntities.Crm" & gt; Latimore & lt; / LastName & gt; & Lt; / Indvidual & gt;

Note the presence of xmlns in elements first and last name - it is added when we make XML by serializing C # commercial object, it seems that elements in this The presence of the namespace is causing the XQuery expression to fail, such as: 

  SELECT MyTable.value ('(// personal / last name) [1]', 'Newcomer (100) ') First name

This return is taped. But when I remove namespace from elements in XML (for example use a T-SQL statement), then gives a description of the value given above. However, there should be a better way - is there any way to make this question, without updating XML first?

Thanks

John Davis

Must have to give the name exactly which you want to choose. See . Here is an example using your XML: 

  declared @ x xml; Set @ x = n '& lt; Personalized xmlns: xsi = "http://www.w3.org/2001/XMLSchema-instance" xmlns: xsd = "http://www.w3.org/2001/XMLSchema" & gt; & Lt; Firstname xmlns = "http://nswcc.org.au/BusinessEntities.Crm" & gt; Liria & lt; / FirstName & gt; & Lt; LastName xmlns = "http://nswcc.org.au/BusinessEntities.Crm" & gt; Latimore & lt; / LastName & gt; & Lt; / Personal & gt; '; With Xmlnamespaces (N'http: //nswcc.org.au/BusinessEntities.Crm as CRM) select @x.value (n '(// personal / CRM: lastname) [1]', 'N'InWorker (100) ') AS First Name

Comments

Post a Comment

Popular posts from this blog

MySql variables and php -

-
I am getting an error with php in order to format mysql_query () in php to format this string What is the right way? SELECT SELECT SELECT (*) Agents @AgentCount; User_Agent_English, User_Angent_Oursal, US.___Gent_Aginal, COUNT (User_Agent_Percade) ACC, COUNT (*) / (AgentCount) Percentage by agents user_agent_preser order DEC limit limit 50; In PHP, how am i setting $ query $ query = "SELECT count (*) agents @ agentcount; SELECT user_agent_parsed, User_agent_original , COUNT (user_agent_parsed) ascount, COUNT (*) / (@AgentCount) as a percentage by user_agent_parced by URI date DESC limit 50 "; This exact query will work properly if I put it in MySQL directly through a command line session. Do I need to release two separate php calls from mysql_query () and store the results first? I get the following error: There is an error in your SQL syntax; Instead of using a sub-selection and instead of using the 'SELECT user_agent_parsed, user_agent_original, ne...
Read more

php - Laravel - Overriding a resource route into a different route filter group -

-
Does Laravel's routing work as expected? What I think, if I want to override a route, then I just have to give the expected route before each other. I have something like this: root :: group (array ('first' = & gt; 'defaultLoads' =); function () {root :: post 'Newsletter', 'newsletter controller @ store'); root: group (array ('(newsletter', 'newsletter controller');}}); That if I post this route, only http://domain.com/newsletter should run only the default loads route filter. However, when I call php Runs artisan routes , I get this: | | POST newsletter | newsletter.store | newslettercontroller@ store | default loads | login | | though it reads the route correctly (PHP artisan loads which The correct path is to the right place) but the file of the resource path even if it is not in the filter group, the path is affected. Then my question: How does it work Laravel? If so, do I post this -> Newsle...
Read more

url rewriting - How to implement the returnurl like SO in PHP? -

-
This URL should work even after the rewrite. Is this possible? Otherwise, I can only hardcoded everything If you are trying to create a login system with redirection You need to use the HTTP_REFERER header to find out where the user came from so that you can send it back there. The best way to do this is to use something like this in your login form: // - Login php & Lt; Input type = "password" name = "password" /> & Lt; Input type = "hidden" name = "returnrelale" value = "& lt ;? php echo $ redirectURL ;? & gt;" / & Gt; & Lt; / Form & gt; Please note that some ISP, browser or proxy will delete the referrer header, so you can not rely on each user to work fully. If you use a statement, to check whether the header exists or not, you can send those users back to the homepage or whatever. Edit If you are looking to use $ _SERVER ['REQUEST_URI'], if you are running Apache It sho...
Read more