gdb - how to print result of evaluation for C++ -

-

Ive was looking around but was unable to figure out how to print in GDB in the outcome of an evaluation is. For example, in the code given below: 

  if (strcmp (current_node-> word, min_node- & gt; word) & gt; min_node = current_node;

(Up I was trying a possible method to check the alphabetical order for stars, and it was not certain that it works properly)

Now I can see min_node and if the value changes but this is sometimes more complex in the inserted code, I was wondering if there is an easy way to see the evaluation of a test on the line, where Currently GDB / Programs Week is.

Many thanks!

There is no expression-level single phase in GDB, if you are asking for it.

Your Options (Typically <<>

>

> It is surprising, this works: GDB can evaluate the function call, by executing the code in the ongoing program and executing the code. Of course, it is quite dangerous If the function can have a bad effect or crash; in this case, it is so harmless that people will not usually think of potential problems.
  • The directional level DBly) Single-step (Ni / C). When call is instructed, you find results in a register according to processor conventions (x86% eax).
  • Variables can be used for intermediate To assign values, edit the code, and split it into separate lines; then use regular single-phase and observe the variable.

    • Comments

    Post a Comment

    Popular posts from this blog

    MySql variables and php -

    -
    I am getting an error with php in order to format mysql_query () in php to format this string What is the right way? SELECT SELECT SELECT (*) Agents @AgentCount; User_Agent_English, User_Angent_Oursal, US.___Gent_Aginal, COUNT (User_Agent_Percade) ACC, COUNT (*) / (AgentCount) Percentage by agents user_agent_preser order DEC limit limit 50; In PHP, how am i setting $ query $ query = "SELECT count (*) agents @ agentcount; SELECT user_agent_parsed, User_agent_original , COUNT (user_agent_parsed) ascount, COUNT (*) / (@AgentCount) as a percentage by user_agent_parced by URI date DESC limit 50 "; This exact query will work properly if I put it in MySQL directly through a command line session. Do I need to release two separate php calls from mysql_query () and store the results first? I get the following error: There is an error in your SQL syntax; Instead of using a sub-selection and instead of using the 'SELECT user_agent_parsed, user_agent_original, ne...
    Read more

    php - Laravel - Overriding a resource route into a different route filter group -

    -
    Does Laravel's routing work as expected? What I think, if I want to override a route, then I just have to give the expected route before each other. I have something like this: root :: group (array ('first' = & gt; 'defaultLoads' =); function () {root :: post 'Newsletter', 'newsletter controller @ store'); root: group (array ('(newsletter', 'newsletter controller');}}); That if I post this route, only http://domain.com/newsletter should run only the default loads route filter. However, when I call php Runs artisan routes , I get this: | | POST newsletter | newsletter.store | newslettercontroller@ store | default loads | login | | though it reads the route correctly (PHP artisan loads which The correct path is to the right place) but the file of the resource path even if it is not in the filter group, the path is affected. Then my question: How does it work Laravel? If so, do I post this -> Newsle...
    Read more

    url rewriting - How to implement the returnurl like SO in PHP? -

    -
    This URL should work even after the rewrite. Is this possible? Otherwise, I can only hardcoded everything If you are trying to create a login system with redirection You need to use the HTTP_REFERER header to find out where the user came from so that you can send it back there. The best way to do this is to use something like this in your login form: // - Login php & Lt; Input type = "password" name = "password" /> & Lt; Input type = "hidden" name = "returnrelale" value = "& lt ;? php echo $ redirectURL ;? & gt;" / & Gt; & Lt; / Form & gt; Please note that some ISP, browser or proxy will delete the referrer header, so you can not rely on each user to work fully. If you use a statement, to check whether the header exists or not, you can send those users back to the homepage or whatever. Edit If you are looking to use $ _SERVER ['REQUEST_URI'], if you are running Apache It sho...
    Read more