c++ - What is the point of `void func() throw(type)`? -

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I know what it means to throw in a valid C ++ program function declaration? AFAIK it does nothing and is not used for anything. 

  #include & lt; Exceptions & gt; Zero func () throw (std :: exception) {} int main () {return 0; } 
 
 This is an exception specification, and it is almost certainly one.  
 indicates that  func  can throw a  std :: exception , and any other exception that emits  func  The result will be the call.

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