c++ - variable + value macro expansion -

I tried my code without any consequences:

  #include "Stdafx.h" #include & lt; Iostream & gt; #define R () (rand ()) #define H (a, b) (a ##b) #define S (a) (#a) #define CAT () H (S (distinct_name_), R ()) Int main (int argc, _TCHAR * argv []) {std :: cout & lt; & Lt; Cat () & lt; & Lt; Std :: endl; Std :: cout & lt; & Lt; Cat () & lt; & Lt; Std :: endl; Std :: cout & lt; & Lt; Cat () & lt; & Lt; Std :: endl; Return 0; }  

I would like to get a result like this:

  distinct_name_12233 distinct_name_147 distinct_name_435 different-code>  
 Getting: The word 1 does not evaluate the function while taking arguments. Is it worth achieving ??  
 EDIT: In the end, I succeeded after a few hours, the pre-programmer still does weird things which I can not fully understand. Here goes:  
  #include "stdafx.h" #include & lt; Iostream & gt; Class Profiler {Public: Zero Show () {std :: cout & lt; & Lt; "Specific_station" & lt; & Lt; Std :: endl; }}; #define XX __LINE__ #define H (a, b) (a ## b) #define CAT (r) H (distinct_name_, r) #define GET_DISTINCT () CAT (XX) #define PROFILE () \ profiler GET_DISTINCT (); \ GET_DISTINCT () Show (); \ Int main (int argc, _TCHAR * argv []) {PROFILE () PROFILE () 0; }  
 
 And the output is: 
 
  distinct_instance distinct_instance  
 
 thanks  __ line __  hint} 
 

I think many people have already answered the question correctly But, as an alternative suggestion, if your preprocessor's __ time___ or __ line __ is applicable, you can get a line number instead of a result number or Can get a result over time.

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