preg match all - preg_match Vs preg_match_all browser error not php? -

-

हाय सब मेरे पास निम्न है: 

  $ str = base64_encode (preg_replace ("#")  
 
 
 \ S | \ r | \ t | \ n # "," ", file_get_contents (" ../ www.cms.actwebdesigns.co.uk2 / logged.php "))); अगर (preg_replace ("# (PD9waHAg) ((?? (Pz4g))।) * # है", $ str,)) {#print_r ($ मैचों); गूंज "& lt; xmp & gt;"। Base64_decode ($ मैचों [0]। "Pz4g")। "& Lt; / xmp & gt;"; }

अब यह काम करता है लेकिन मैं इसे पृष्ठ पर सभी घटनाओं के लिए उपयोग करने में सक्षम होना चाहता हूं। (पृष्ठ में PHP खंड पाता है) तो मैंने preg_match_all का उपयोग किया है लेकिन एक ब्राउज़र त्रुटि लौटती है (पृष्ठ स्थानांतरित कर दिया गया है या अब मौजूद नहीं है) किसी को भी क्यों पता है?

यह एक असली लंबे समय का है, लेकिन मुझे लगता है कि इंटरनेट एक्सप्लोरर के कुछ संस्करण "फीचर" वाले याद किए गए हैं जहां तथाकथित मैत्रीपूर्ण त्रुटि संदेश उन पृष्ठों के लिए प्रदर्शित किए गए थे :

  • एक त्रुटि स्थिति कोड (जैसे 404 नहीं मिला ) वापस कर दिया गया था, और
  • वास्तविक HTML प्रतिक्रिया एक निश्चित संख्या से छोटी थी बाइट्स।

यदि आपका कोड पहले से ही एक त्रुटि का उत्तर भेज रहा था, और preg_match_all () में परिवर्तन समाप्त हो गया तो पर्याप्त रूप से आउटपुट को छोटा करना, त्रुटि संदेश।

यदि आप IE का उपयोग नहीं कर रहे हैं, या यदि आपकी स्क्रिप्ट गैर-त्रुटि स्थिति कोड वापस कर रही है, तो मुझे नहीं पता कि इसका कारण क्या हो सकता है।


Comments

Post a Comment

Popular posts from this blog

MySql variables and php -

-
I am getting an error with php in order to format mysql_query () in php to format this string What is the right way? SELECT SELECT SELECT (*) Agents @AgentCount; User_Agent_English, User_Angent_Oursal, US.___Gent_Aginal, COUNT (User_Agent_Percade) ACC, COUNT (*) / (AgentCount) Percentage by agents user_agent_preser order DEC limit limit 50; In PHP, how am i setting $ query $ query = "SELECT count (*) agents @ agentcount; SELECT user_agent_parsed, User_agent_original , COUNT (user_agent_parsed) ascount, COUNT (*) / (@AgentCount) as a percentage by user_agent_parced by URI date DESC limit 50 "; This exact query will work properly if I put it in MySQL directly through a command line session. Do I need to release two separate php calls from mysql_query () and store the results first? I get the following error: There is an error in your SQL syntax; Instead of using a sub-selection and instead of using the 'SELECT user_agent_parsed, user_agent_original, ne...
Read more

php - Laravel - Overriding a resource route into a different route filter group -

-
Does Laravel's routing work as expected? What I think, if I want to override a route, then I just have to give the expected route before each other. I have something like this: root :: group (array ('first' = & gt; 'defaultLoads' =); function () {root :: post 'Newsletter', 'newsletter controller @ store'); root: group (array ('(newsletter', 'newsletter controller');}}); That if I post this route, only http://domain.com/newsletter should run only the default loads route filter. However, when I call php Runs artisan routes , I get this: | | POST newsletter | newsletter.store | newslettercontroller@ store | default loads | login | | though it reads the route correctly (PHP artisan loads which The correct path is to the right place) but the file of the resource path even if it is not in the filter group, the path is affected. Then my question: How does it work Laravel? If so, do I post this -> Newsle...
Read more

url rewriting - How to implement the returnurl like SO in PHP? -

-
This URL should work even after the rewrite. Is this possible? Otherwise, I can only hardcoded everything If you are trying to create a login system with redirection You need to use the HTTP_REFERER header to find out where the user came from so that you can send it back there. The best way to do this is to use something like this in your login form: // - Login php & Lt; Input type = "password" name = "password" /> & Lt; Input type = "hidden" name = "returnrelale" value = "& lt ;? php echo $ redirectURL ;? & gt;" / & Gt; & Lt; / Form & gt; Please note that some ISP, browser or proxy will delete the referrer header, so you can not rely on each user to work fully. If you use a statement, to check whether the header exists or not, you can send those users back to the homepage or whatever. Edit If you are looking to use $ _SERVER ['REQUEST_URI'], if you are running Apache It sho...
Read more