Regex match question -

-

अगर मेरे पास स्ट्रिंग है जैसे

lotsofcrap "somethingimportant" अधिकotherस्टफ़

क्या Regex को मिलान करने के लिए संभव है, जो "" उद्धरण चिह्नों को छोड़कर के बीच में है। तो यह पता लगाने का तरीका "। *" जैसा कुछ होगा, लेकिन वह सिर्फ शुद्ध कुछ महत्वहीन के बजाय "महत्वहीन" P> 

  "। (। *)"

आप उपयोग कर सकते हैं एक कैप्चरिंग समूह बनाने के लिए मापदंड आप इसका उपयोग कैसे करते हैं यह उस भाषा / लाइब्रेरी पर निर्भर करता है जो आप उपयोग कर रहे हैं - आम तौर पर कैप्चर समूह प्रील-जैसे भाषाओं में $ 1 या \ 1 के रूप में उपलब्ध हैं उदाहरण के लिए, पर्ल में: 

  'हैलो' विश्व "!!!" = ~ /"(.*)"/; प्रिंट करें "$ 1 \ n";

Comments

Post a Comment

Popular posts from this blog

ios - Form Sheet content disappearing -

-
Image
I am trying to apply a form sheet. Looks like this on the storyboard: App background only when I run Appears and everything else is hidden. I am presenting a form sheet using model sheets - I am working with the form sheet and I (WREGLR Regular) size. Why is this happening?
Read more

MySql variables and php -

-
I am getting an error with php in order to format mysql_query () in php to format this string What is the right way? SELECT SELECT SELECT (*) Agents @AgentCount; User_Agent_English, User_Angent_Oursal, US.___Gent_Aginal, COUNT (User_Agent_Percade) ACC, COUNT (*) / (AgentCount) Percentage by agents user_agent_preser order DEC limit limit 50; In PHP, how am i setting $ query $ query = "SELECT count (*) agents @ agentcount; SELECT user_agent_parsed, User_agent_original , COUNT (user_agent_parsed) ascount, COUNT (*) / (@AgentCount) as a percentage by user_agent_parced by URI date DESC limit 50 "; This exact query will work properly if I put it in MySQL directly through a command line session. Do I need to release two separate php calls from mysql_query () and store the results first? I get the following error: There is an error in your SQL syntax; Instead of using a sub-selection and instead of using the 'SELECT user_agent_parsed, user_agent_original, ne...
Read more

Lists in scheme -

-
I am trying to write a function in the plan that takes every item list and class in the list, then returns the list As is (list xyz) . However, I'm not sure how to write a code that would do this. So far, I have (defined (category = list list) (cond [(empty? List) false) [and (list (SQL) (first A-list)) (Square-list) (The rest is a list)))]) but it returns to the list (cons y (cons z empty)) What can I do to return it to the list only in (list xyz) ? Thanks! You're almost there - make sure you type cons and List (The text book explains this section 13. You can find copies online). Conflict The first element for the 'rest' part and (usually) one (potentially empty) list as an example, (Opposition 1 blank) Number 1 as its first element and the empty list is in the form of 'rest' (Opposition 1 (Opposition 2 Empty)) No. 1 before Element, and (Opposition 2 empty) is in the form of 'rest'. List is just a simple shorth...
Read more