c++ - Virtual non-method members -

Is this possible? This way it generates an error.

  class A {public: virtual std :: string key; }; Class B: Public A {Public: std :: string key; }; Int main (A); A.key = "Foo"; Return 1; }   
 
 
 No, because it really does not make sense to remember that sub- In the class there are all members of its original class; Therefore,  b  is still  a  's  std :: string key . Also, since  b  is of  std :: string key  is the same type, it is  very similar  to  a  s - So, what was the issue of overriding it? 
 
 Also, note that during the construction, when we will not be asked the virtual methods of the creator of  A , it means that If we arrive at the construction of  A  during the  key , then we get the key of  A  - but then when  B < / Code> is created, that  key  is shaded, its data is completely inaccessible. 
 
 He said, if you really want to do something like that, you will need to use a virtual accelerator function: 
 
  class A {private: std: : String m_key; Public: Virtual std :: string and key () {return m_key; } Virtual const std :: string and key () const {returns m_key; }}; Class B: Public A {Private: std :: string m_key; Public: Virtual std :: string and key () {return m_key; } Virtual const std :: string and key () const {returns m_key; }}; Int main () {B b; B.K. () = "Foo"; Return 0; }